Create a globally partitioned range index

CREATE TABLE SCOTT.ARCHIVED_NOTES
(
  NOTE_ID                     NUMBER(10)        NOT NULL,
  PPT_ID                      NUMBER(10),
  REGISTRED_DATE              DATE              NOT NULL,
  EDITED_DATE                 DATE,
  ALTERED_BY                  VARCHAR2(30 BYTE) NOT NULL,
  ALTERED_DATE                DATE              NOT NULL,
  CONTENT_CODE                VARCHAR2(4 BYTE),
  NOTEFORMAT                  VARCHAR2(1 BYTE)
)
TABLESPACE USERS
PARTITION BY RANGE (NOTE_ID)
(  
  PARTITION ARCHIVED20 VALUES LESS THAN (21000000),  
  PARTITION ARCHIVED21 VALUES LESS THAN (22000000),
  PARTITION ARCHIVED22 VALUES LESS THAN (23000000)
)
;

Create a global range partitioned index. Notice the GLOBAL keyword:

CREATE INDEX SCOTT.ARCHIVED_NOTES_IDX1 
ON SCOTT.ARCHIVED_NOTES(NOTE_ID)
GLOBAL PARTITION BY RANGE(NOTE_ID)(  
  PARTITION ARCHIVED20 VALUES LESS THAN (21000000),  
  PARTITION ARCHIVED21 VALUES LESS THAN (22000000),  
  PARTITION ARCHIVED22 VALUES LESS THAN (23000000),
  PARTITION ARCHIVED_OTHERS VALUES LESS THAN (MAXVALUE)
);

Also note that Oracle required the MAXVALUES clause as the last partition in the index, to ensure that all rows in the table will be represented in the index. Without MAXVALUES, Oracle will throw the error:

ORA-14021: MAXVALUE must be specified for all columns

Verify its existence:

SELECT INDEX_NAME,PARTITION_NAME 
FROM USER_IND_PARTITIONS 
WHERE INDEX_NAME = (SELECT INDEX_NAME FROM USER_INDEXES WHERE TABLE_NAME='ARCHIVED_NOTES'); 

INDEX_NAME	PARTITION_NAME
ARCHIVED_NOTES_IDX1	ARCHIVED20
ARCHIVED_NOTES_IDX1	ARCHIVED21
ARCHIVED_NOTES_IDX1	ARCHIVED22
ARCHIVED_NOTES_IDX1	ARCHIVED_OTHERS

You could also make the index UNIQUE:

CREATE UNIQUE INDEX SCOTT.ARCHIVED_NOTES_IDX1 ... 

A unique index like this could support a primary key constraint on the table, if desirable:

ALTER TABLE ARCHIVED_NOTES ADD CONSTRAINT ARCHIVED_NOTES_PK
PRIMARY KEY (NOTE_ID)
USING INDEX ARCHIVED_NOTES_IDX1;

Let's take a deeper look at the index Properties:

SELECT C.TABLE_NAME,I.INDEX_NAME,I.PARTITIONING_TYPE, I.SUBPARTITIONING_TYPE, I.LOCALITY,I.ALIGNMENT,C.COLUMN_NAME,C.COLUMN_POSITION
FROM USER_PART_INDEXES I JOIN USER_IND_COLUMNS C
ON (I.INDEX_NAME = C.INDEX_NAME)
WHERE I.TABLE_NAME IN (SELECT TABLE_NAME FROM USER_TABLES WHERE PARTITIONED='YES')
ORDER BY 1,2,7;

TABLE_NAME	INDEX_NAME	PARTITIONING_TYPE	SUBPARTITIONING_TYPE	LOCALITY	ALIGNMENT	COLUMN_NAME	COLUMN_POSITION
ARCHIVED_NOTES	ARCHIVED_NOTES_IDX1	RANGE	NONE	GLOBAL	PREFIXED	NOTE_ID	1

For globally partitioned indexes, the "alignment" column will always show the index as "prefixed". This is the only supported index type for global partitioned indexes.

An important point regarding globally partitioned indexes is pointed out in the Oracle Documentation:

"Normally, a global index is not equipartitioned with the underlying table."

and

"There is nothing to prevent an index from being equipartitioned with the underlying table, but Oracle does not take advantage of the equipartitioning when generating query plans or executing partition maintenance operations. So an index that is equipartitioned with the underlying table should be created as LOCAL."

In other words, while the example above would work, it may not be a good idea. It would make better sense for the global partitioned index to be created on another column:

CREATE INDEX SCOTT.ARCHIVED_NOTES_IDX1 
ON SCOTT.ARCHIVED_NOTES(REGISTRED_DATE)
GLOBAL PARTITION BY RANGE(REGISTRED_DATE)(  
  PARTITION NOTES_2012 VALUES LESS THAN (to_date('01.01.2013', 'dd.mm.yyyy')),  
  PARTITION NOTES_2013 VALUES LESS THAN (to_date('01.01.2014', 'dd.mm.yyyy')),  
  PARTITION NOTES_2014 VALUES LESS THAN (to_date('01.01.2015', 'dd.mm.yyyy'))
  ,PARTITION ARCHIVED_OTHERS VALUES LESS THAN (MAXVALUE)
);

Create a local non-prefixed partitioned index

The table below is partitioned by range, using the column NOTE_ID as the partition key:

CREATE TABLE SCOTT.ARCHIVED_NOTES
(
  NOTE_ID                     NUMBER(10)        NOT NULL,
  PPT_ID                      NUMBER(10),
  REGISTRED_DATE              DATE              NOT NULL,
  EDITED_DATE                 DATE,
  ALTERED_BY                  VARCHAR2(30 BYTE) NOT NULL,
  ALTERED_DATE                DATE              NOT NULL,
  CONTENT_CODE                VARCHAR2(4 BYTE),
  NOTEFORMAT                  VARCHAR2(1 BYTE)
)
TABLESPACE USERS
PARTITION BY RANGE (NOTE_ID)
(  
  PARTITION ARCHIVED20 VALUES LESS THAN (21000000),  
  PARTITION ARCHIVED21 VALUES LESS THAN (22000000),
  PARTITION ARCHIVED22 VALUES LESS THAN (23000000)
)
;

Create a global partitioned index:

CREATE INDEX SCOTT.REGISTRED_DATE_SK1 ON SCOTT.ARCHIVED_NOTES
(REGISTRED_DATE)
LOCAL (  
  PARTITION ARCHIVED20,  
  PARTITION ARCHIVED21,  
  PARTITION ARCHIVED22
)

Confirm its existence:

SELECT INDEX_NAME,PARTITIONED
FROM USER_INDEXES
WHERE TABLE_NAME='ARCHIVED_NOTES';

INDEX_NAME	PARTITIONED
REGISTRED_DATE_SK1	YES

Confirm that the expected index partitions have been created:

SELECT INDEX_NAME,PARTITION_NAME 
FROM USER_IND_PARTITIONS 
WHERE INDEX_NAME = (SELECT INDEX_NAME FROM USER_INDEXES WHERE TABLE_NAME='ARCHIVED_NOTES'); 

INDEX_NAME	PARTITION_NAME
REGISTRED_DATE_SK1	ARCHIVED20
REGISTRED_DATE_SK1	ARCHIVED21
REGISTRED_DATE_SK1	ARCHIVED22

Add a new partition:

ALTER TABLE SCOTT.ARCHIVED_NOTES
 ADD 
  PARTITION ARCHIVED23 VALUES LESS THAN (24000000);

If you confirm the index partitions again, you'll see that a new index partition has been added:

INDEX_NAME	PARTITION_NAME
REGISTRED_DATE_SK1	ARCHIVED23

Let's take a deeper look at the properties of this index:

SELECT C.TABLE_NAME,I.INDEX_NAME,I.PARTITIONING_TYPE, I.SUBPARTITIONING_TYPE, I.LOCALITY,I.ALIGNMENT,C.COLUMN_NAME,C.COLUMN_POSITION
FROM USER_PART_INDEXES I JOIN USER_IND_COLUMNS C
ON (I.INDEX_NAME = C.INDEX_NAME)
WHERE I.TABLE_NAME IN (SELECT TABLE_NAME FROM USER_TABLES WHERE PARTITIONED='YES')
ORDER BY 1,2,7;

TABLE_NAME	INDEX_NAME	PARTITIONING_TYPE	SUBPARTITIONING_TYPE	LOCALITY	ALIGNMENT	COLUMN_NAME	COLUMN_POSITION
ARCHIVED_NOTES	REGISTRED_DATE_SK1	RANGE	NONE	LOCAL	NON_PREFIXED	REGISTRED_DATE	1

The "alignment" column of the above output reveals that the index is of type "non_prefixed", which means that the partitioning key is not the first column in the index.

Create a local prefixed partitioned index

The table below is partitioned by range, using the column NOTE_ID as the partition key:

CREATE TABLE SCOTT.ARCHIVED_NOTES
(
  NOTE_ID                     NUMBER(10)        NOT NULL,
  PPT_ID                      NUMBER(10),
  REGISTRED_DATE              DATE              NOT NULL,
  EDITED_DATE                 DATE,
  ALTERED_BY                  VARCHAR2(30 BYTE) NOT NULL,
  ALTERED_DATE                DATE              NOT NULL,
  CONTENT_CODE                VARCHAR2(4 BYTE),
  NOTEFORMAT                  VARCHAR2(1 BYTE)
)
TABLESPACE USERS
PARTITION BY RANGE (NOTE_ID)
(  
  PARTITION ARCHIVED20 VALUES LESS THAN (21000000),  
  PARTITION ARCHIVED21 VALUES LESS THAN (22000000),
  PARTITION ARCHIVED22 VALUES LESS THAN (23000000)
)
;

Create a local index:

CREATE UNIQUE INDEX SCOTT.ARCHIVED_NOTES_PK ON SCOTT.ARCHIVED_NOTES
(NOTE_ID)
LOCAL (  
  PARTITION ARCHIVED20,  
  PARTITION ARCHIVED21,  
  PARTITION ARCHIVED22
);

Confirm its existence:

INDEX_NAME	PARTITIONED
ARCHIVED_NOTES_PK	YES

The index we just created can be used to support a unique or a primary key constraint:

ALTER TABLE ARCHIVED_NOTES ADD CONSTRAINT ARCHIVED_NOTES_PK
PRIMARY KEY (NOTE_ID)
USING INDEX ARCHIVED_NOTES_PK;

Confirm that the expected index partitions have been created:

SELECT INDEX_NAME,PARTITION_NAME 
FROM USER_IND_PARTITIONS 
WHERE INDEX_NAME = (SELECT INDEX_NAME FROM USER_INDEXES WHERE TABLE_NAME='ARCHIVED_NOTES'); 

INDEX_NAME	PARTITION_NAME
ARCHIVED_NOTES_PK	ARCHIVED20
ARCHIVED_NOTES_PK	ARCHIVED21
ARCHIVED_NOTES_PK	ARCHIVED22

Add a new partition:

ALTER TABLE SCOTT.ARCHIVED_NOTES
 ADD 
  PARTITION ARCHIVED23 VALUES LESS THAN (23000000);

If you confirm the index partitions again, you'll see that a new index partition has been added:

INDEX_NAME	PARTITION_NAME
ARCHIVED_NOTES_PK	ARCHIVED23

Let's take a deeper look at the properties of this index:

SELECT C.TABLE_NAME,I.INDEX_NAME,I.PARTITIONING_TYPE, I.SUBPARTITIONING_TYPE, I.LOCALITY,I.ALIGNMENT,C.COLUMN_NAME,C.COLUMN_POSITION
FROM USER_PART_INDEXES I JOIN USER_IND_COLUMNS C
ON (I.INDEX_NAME = C.INDEX_NAME)
WHERE I.TABLE_NAME IN (SELECT TABLE_NAME FROM USER_TABLES WHERE PARTITIONED='YES')
ORDER BY 1,2,7;

TABLE_NAME	INDEX_NAME	PARTITIONING_TYPE	SUBPARTITIONING_TYPE	LOCALITY	ALIGNMENT	COLUMN_NAME	COLUMN_POSITION
ARCHIVED_NOTES	ARCHIVED_NOTES_PK	RANGE	NONE	LOCAL	PREFIXED	NOTE_ID	1

The "alignment" column of the above output reveals that the index is of type "prefixed", which means that the partitioning key is the first column in the index.

How to lock table statstics in Oracle

Use dbms_stats.lock_table_stats

conn scott
exec dbms_stats.lock_table_stats('SCOTT','DEPT');

Verify the setting:

select table_name,object_type,stattype_locked 
from user_tab_statistics;

TABLE_NAME                     OBJECT_TYPE                          STATTYPE_LOCKED
------------------------------ ------------------------------------ ---------------
DEPT                           TABLE                                ALL
EMP                            TABLE
BONUS                          TABLE
SALGRADE                       TABLE
RECEIVED_DOCUMENTS             TABLE

Lock stats on a specific partition:

exec dbms_stats.lock_partition_stats('SCOTT','RECEIVED_DOCUMENTS','SETTELM');

Verify the setting:

select table_name,partition_name,subpartition_name,object_type,stattype_locked 
from user_tab_statistics 
where table_name='RECEIVED_DOCUMENTS';

TABLE_NAME                     PARTITION_NAME  SUBPARTITION_NAME OBJECT_TYPE          STATTYPE_LOCKED
------------------------------ --------------- ----------------- -------------------- ---------------
RECEIVED_DOCUMENTS                                               TABLE
RECEIVED_DOCUMENTS             APPLICANT                         PARTITION
RECEIVED_DOCUMENTS             APPLICATIONS                      PARTITION
RECEIVED_DOCUMENTS             SETTELM                           PARTITION            ALL

To reverse the process:

exec dbms_stats.unlock_table_stats('SCOTT','DEPT);
exec dbms_stats.unlock_partition_stats('SCOTT','RECEIVED_DOCUMENTS','SETTELM');

How to check if the "gather_database_stats" automatic maintenance jobs has succseeded

select id,operation,to_char(start_time,'dd.mm.yyyy hh24:mi:ss') "starttime",
                        to_char(end_Time,'dd.mm.yyyy hh24:mi:ss') "endtime",
                        to_dsinterval(to_char(end_time-start_Time,'dd.mm.yyyy hh24:mi:ss')) "elapsed",
                        status,job_name
from DBA_OPTSTAT_OPERATIONS
where operation = 'gather_database_stats (auto)'
order by start_time desc
fetch first 5 rows only;

Gave the following result:

ID	OPERATION	starttime	endtime	elapsed	STATUS	JOB_NAME
58778	gather_database_stats (auto)	07.02.2017 22:00:02	08.02.2017 02:00:15	+00 04:00:13.178197	TIMED OUT	ORA$AT_OS_OPT_SY_1965
58585	gather_database_stats (auto)	06.02.2017 22:00:06	07.02.2017 02:00:24	+00 04:00:18.089479	TIMED OUT	ORA$AT_OS_OPT_SY_1963
58273	gather_database_stats (auto)	05.02.2017 06:00:04	06.02.2017 02:00:26	+00 20:00:21.968028	TIMED OUT	ORA$AT_OS_OPT_SY_1950
58088	gather_database_stats (auto)	04.02.2017 06:00:02	05.02.2017 02:00:32	+00 20:00:29.696085	TIMED OUT	ORA$AT_OS_OPT_SY_1945
58038	gather_database_stats (auto)	03.02.2017 22:00:02	04.02.2017 02:00:17	+00 04:00:15.314408	TIMED OUT	ORA$AT_OS_OPT_SY_1943

The output indicates that the Automatic maintenance job never get to finish before the maintenance Windows Closes.

You can examine another view, dba_opstat_operation_tasks, to see the details on what the job didn't have time to do before the window closed:

select  opid, target,target_type, 
        to_char(start_Time,'dd.mm.yyyy hh24:mi:ss') "starttime",
        to_char(end_time,'dd.mm.yyyy hh24:mi:ss') "endtime"
        ,status
from dba_optstat_operation_tasks 
where opid=58778
order by start_Time desc
;

Sample output:

OPID	TARGET	TARGET_TYPE	starttime	endtime	STATUS
58778	SCOTT.TABLE1.SYS_SUBP25275	TABLE	08.02.2017 02:00:11	08.02.2017 02:00:11	TIMED OUT
58778	SCOTT.TABLE1.SYS_SUBP25267	TABLE	08.02.2017 02:00:11	08.02.2017 02:00:11	TIMED OUT

Notice how the starttime and endtime is identical; this is because the window Closes, and the job aborts. Oracle then records this timestamp as the start time and end time for the Objects it never had time to analyze.

The Predefined Maintenance Windows in Oracle 12c

Oracle documentation states:

"By default there are seven predefined maintenance windows, each one representing a day of the week. The weekend maintenance windows, SATURDAY_WINDOW and SUNDAY_WINDOW, are longer in duration than the weekday maintenance windows. The window group MAINTENANCE_WINDOW_GROUP consists of these seven windows."

Verify by executing:

SELECT WINDOW_NAME,REPEAT_INTERVAL,DURATION,to_char(LAST_START_DATE,'dd.mm.yyyy hh24:mi') "laststart",
    to_char(NEXT_START_DATE,'dd.mm.yyyy hh24:mi') "nextstart",ENABLED "window enabled?",ACTIVE "window open?"
FROM DBA_SCHEDULER_WINDOWS 
WHERE RESOURCE_PLAN='DEFAULT_MAINTENANCE_PLAN';

WINDOW_NAME	REPEAT_INTERVAL	DURATION	laststart	nextstart	window enabled?	window open?
SUNDAY_WINDOW	freq=daily;byday=SUN;byhour=6;byminute=0; bysecond=0	+00 20:00:00.000000	05.02.2017 06:00	12.02.2017 06:00	TRUE	FALSE
SATURDAY_WINDOW	freq=daily;byday=SAT;byhour=6;byminute=0; bysecond=0	+00 20:00:00.000000	04.02.2017 06:00	11.02.2017 06:00	TRUE	FALSE
FRIDAY_WINDOW	freq=daily;byday=FRI;byhour=22;byminute=0; bysecond=0	+00 04:00:00.000000	03.02.2017 22:00	10.02.2017 22:00	TRUE	FALSE
THURSDAY_WINDOW	freq=daily;byday=THU;byhour=22;byminute=0; bysecond=0	+00 04:00:00.000000	02.02.2017 22:00	09.02.2017 22:00	TRUE	FALSE
WEDNESDAY_WINDOW	freq=daily;byday=WED;byhour=22;byminute=0; bysecond=0	+00 04:00:00.000000	01.02.2017 22:00	08.02.2017 22:00	TRUE	FALSE
TUESDAY_WINDOW	freq=daily;byday=TUE;byhour=22;byminute=0; bysecond=0	+00 04:00:00.000000	07.02.2017 22:00	14.02.2017 22:00	TRUE	FALSE
MONDAY_WINDOW	freq=daily;byday=MON;byhour=22;byminute=0; bysecond=0	+00 04:00:00.000000	06.02.2017 22:00	13.02.2017 22:00	TRUE	FALSE

The weekend Windows starts at 6 in the morning and run for 20 hours.
The weekday Windows starts at 22:00 and runs until 02:00 in the morning.

An overview of some important data Dictionary views can be found here

How to display a SYSTIMESTAMP data type as a TIMESTAMP WITH TZ

To display a value of datatype SYSTIMESTAMP as TIMESTAMP WITH TIME ZONE, use TO_CHAR first, then convert to TIMESTAMP WITH TIMEZONE.

The last expression adds one hour, which can be done after the conversion between the datatypes is complete:

select  TO_CHAR(SYSTIMESTAMP,'yyyy/mm/dd hh24:mi:ss.ff tzh:tzm'),
        TO_TIMESTAMP_TZ(to_char(SYSTIMESTAMP,'yyyy/mm/dd hh24:mi:ss.ff tzh:tzm'),'yyyy/mm/dd hh24:mi:ss.ff tzh:tzm'),
        TO_TIMESTAMP_TZ(to_char(SYSTIMESTAMP,'yyyy/mm/dd hh24:mi:ss.ff tzh:tzm'),'yyyy/mm/dd hh24:mi:ss.ff tzh:tzm')+1/24
from dual;

systimestamp	TIMESTAMP_TZ	TIMESTAMP_TZ + 1hr
2017/02/01 10:36:28.158921 +01:00	01/02/2017 10:36:28,158921000 +01:00	01.02.2017 11:36:28